Relation of similarity of Triangles
Equation
$\displaystyle\frac{\bar{AB}}{\bar{A'B'}}=\displaystyle\frac{\bar{AC}}{\bar{A'C'}}=\displaystyle\frac{\bar{BC}}{\bar{B'C'}}$
ID:(3263, 0)
$\displaystyle\frac{\bar{AB}}{\bar{A'B'}}=\displaystyle\frac{\bar{AC}}{\bar{A'C'}}=\displaystyle\frac{\bar{BC}}{\bar{B'C'}}$
ID:(3263, 0)