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Electrocardiograma
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ID:(336, 0)


Circular motion in magnetic field
Equation

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The magnetic component of the Lorentz force

$ F = q v B \sin \theta $



It is always perpendicular to the direction of movement leading to the particle moving in a circle (the speed is tangential to it and thus always orthogonal to the radius). The radius will have to be such that the magnetic force is equal to the centrifugal force so it will have to

$ m \displaystyle\frac{ v ^2}{ r }= q v B $

ID:(3229, 0)


Electrocardiogram
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ID:(1938, 0)


Heart
Description

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ID:(804, 0)


Lorenz Law
Equation

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The force \vec{F} that represents mathematically as current the electric fields \vec{E} and magnetic \vec{B} on a particle is called Lorentz's law. If the particle charge is q and it has a velocity \vec{v} the Lorentz force will be

$ \vec{F} = q ( \vec{E} + \vec{v} \times \vec{B} )$

ID:(3219, 0)


Magnitude of the magnetic component of the Lorentz force
Equation

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The magnetic component of the Lorentz force is

$ \vec{F} = q \vec{v} \times \vec{B} $



so with



its magnitude will be

$ F = q v B \sin \theta $

ID:(3873, 0)


Phases of Heartbeat
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ID:(1939, 0)


Polarization during Heartbeat
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ID:(1940, 0)


Radius of the orbit in the magnetic field
Equation

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Being the movement of an electric charge in a circular magnetic field satisfying the equality between the magnetic and centrifugal forces

$ m \displaystyle\frac{ v ^2}{ r }= q v B $



it will have that the radius of the orbit will be

$ r =\displaystyle\frac{ m v }{ q B }$

ID:(3874, 0)