Druyd:Knowledge

Ideal Gas Partition Function

Storyboard

A simple application of the partition function is achieved by studying the case of an ideal gas.

>Model

ID:(177, 0)

Ideal Gas Partition Function

Model

A simple application of the partition function is achieved by studying the case of an ideal gas.

Variables

Symbol

Text

Variable

Value

Units

Calculate

MKS Value

MKS Units

$\beta$

beta

Beta

1/J

$C_p$

C_p

Capacidad calorica a presión constante

J/K

$C_V$

C_V

Capacidad calorica a volumen constante

J/K

$k_p$

k_p

Compresibilidad isotermica

1/Pa

$k_B$

k_B

Constante de Boltzmann

J/K

$h$

Constante de Planck

J s

$\rho$

rho

Densidad del medio

m/s

$k_T$

k_T

Dilatación térmica

1/K

$E$

Energía del sistema

$Z$

Función partición

$m$

Masa de la partícula

$N$

Numero de partículas

$p$

Presión

$T$

Temperatura

$c$

Velocidad del sonido

m/s

$V$

Volumen

m^3

Calculations

Equation

Number

First, select the equation:

, then, select the variable:

Symbol

Equation

Solved

Translated

Calculations

Symbol

Equation

Solved

Translated

Variable

Given

Calculate

Target :

Equation

To be used

Equations

$ Z =\displaystyle\frac{1}{ h ^{3 N }}\left(\displaystyle\frac{2 \pi m }{ \beta }\right)^{3 N /2} V ^ N $

Z =(2* pi * m / beta )^(3* N /2)* V ^ N /( h ^(3* N ))

(ID 819)

$ C_V =\displaystyle\frac{3 N k_B }{2}$

C_V =3* N k_B /2

(ID 4759)

$ k_p =\displaystyle\frac{1}{ p }$

k_p =1/ p

(ID 4762)

$ k_T =\displaystyle\frac{1}{ T }$

k_T =1/ T

(ID 4763)

$ C_p = \displaystyle\frac{5 N k_B }{2}$

C_p =5 * N * k_B /2

(ID 4766)

$ c ^2=\displaystyle\frac{ p }{ \rho }$

c ^2= p / rho

(ID 7982)

$ E =\displaystyle\frac{3 N }{2 \beta }$

E =3* N /(2* beta )

(ID 7983)

Examples

ID:(177, 0)